\(6 \%\) of the power supplied to a cable appears at the output terminals. Determine the power loss in decibels.
If \(P_{1} =\) input power and \(P_{2} =\) output power then
\(\frac{P_{2}}{P_{1}}=\frac{6}{100}=0.06\)\(\begin{matrix} Decibel\\ power\: ratio \end{matrix}=10\, lg\, (\frac{P_{2}}{P_{1}})=10\, lg\, (0.06)\) \(=10(\, -1.222)=\, -12.22\, dB\)
\(\textbf{Hence the decibel power loss, or attenuation, is 12.22 dB.}\)